Question

# An LC oscillator has L = 60 mH and C = 4.0 μF. If the current...

An LC oscillator has L = 60 mH and C = 4.0 μF. If the current is maximum at t = 0, what will be the first time when the capacitor has maximum charge? Express your answer in ms (milliseconds).

In the ideal LC osciilation circuit.

There is an oscilattion of energy betwwen capacitor and inductor.

When the current is maximum all the energy is stored in inductor E = 1/2xLI2

When the current is zero OR the charge on capacitor is amximum all the energy is stored in capacitor E = Q2/2C

Esentially , in ideal case we must have

1/2xLI2 = = Q2/2C

The angular frequency is given by = (1/LC)1/2

and time period for this is oscillatin is given by T = 2π/ = 2π(LC)1/2

which give frequecy = 1/T Hz = 1/ 2π(LC)1/2

Here we need to find the time

T = 2π(LC)1/2 given

L = 60 mH = 60x 10-3 H

C = 4 F = 4 x 10-6 F

=> T = 2π ( 60x 10-3 x 4 x 10-6 )1/2 = 2π (24)1/2 x 10-4 s = 2π (24)1/2 x 10-1​​​​​ ms = 3.078 ms

-=-=-=-=

Hope it helps!

Have a noce day!

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