Question

A ball is shot from the ground into the air. At a height of
10.80 *m*, the velocity is observed to be **v** = (8.10
*m/s*) **i** + (7.10 *m/s*) **j**.

What is the maximum height that the ball will rise?

What will be the total horizontal distance
traveled by the ball?

What is the *x*-component of the
final velocity of the ball?

What is the *y*-component of the final velocity of the ball
when it lands back on the ground?

Answer #1

**Hmax = h + v0y^2/(2*g)**

** = 10.8 + 7.1^2/(2*9.8)**

** = 13.372 m
<<<<<<<<<<<----Answer**

**time taken to reach same height in air**

**t1 = 2*voy/g = 2*7.1/9.8 = 1.449 s**

**let t2 is the time taken to rach ground**

**y = voy*t + 0.5*g*t^2**

**10.8 = 7.1*t2 + 4.9*t2^2**

**4.9*t2^2 + 7.1*t2 - 10.8 = 0**

**solving the above equation we get**

**t2 = 1.001 s**

**so total time taken, t = t1+t2 = 2.45 s**

**x = Vox*t = 8.1*2.45 = 19.845 m
<<<<<<<---answer**

**vx = vox = 8.1 m/s
<<<<<---Answer**

**vy = -voy - g*t2 = -7.1 - 9.8*1.001 = -16.9 m/s
<<<<<<---Answer**

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