Question

A beam of protons, each with energy E=20 MeV, is incident on a potential step 40...

A beam of protons, each with energy E=20 MeV, is incident on a potential step 40 MeV high. Graph using a computer the relative probability of finding protons at values of x > 0 from x = 0 to x = 5 fm.

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Answer #1

For tunneling, probabilty at a distance x from the start of barrier is given by

where U is potential = 40MeV=40*1.6*10-13J

E=20MeV=20*1.6*10-13J

m=6.67*10-27kg

Taking proportionality constant 1, the given function will be exponential decaying with

P(0fm)=1

P(5fm)=2.78*10-9

The plot of relative probability is given below

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