A SUV manufacturer puts out 2 models of SUV - both with the same body shape (use the streamlined truck C_D of 0.55 if necessary) and the same quality of wheels and bearings, but model B (for "Bigger") is twice as big as model A - twice as wide, twice as tall, twice as long, and 8 times as heavy. At the same speed, the force of aerodynamic drag on model B will be:
B) 8 times larger than on model A
C) the same as on model A
D) 4 times smaller than on model A
E) 4 times larger than on model A
F) 8 times smaller than on model A
1) The aerodynamic drag is proportional to the area of the front surface of the vehicle.
Here, the width and the height of the vehicle B is twice as that of A
So, the area will be 4 times larger.
and the drag will also be 4 times larger.
Option E is correct.
2) The rolling friction is proportional to the mass of the vehicle.
Mass of B = 8 times mass of A (larger).
So, rolling friction = 8 times larger than that of A
Option C is correct.
3) The air drag is dominant compared to rolling friction for a car.
So, the drag force is 4 times for car B
The applied force must also be 4 times , so that a hill can be climbed.
Option F is correct.
4) As in C, engine B must provide 4 times more force to travel at the same velocity.
Since the force is same, the car B will be decelerating.
Option B is correct.
Get Answers For Free
Most questions answered within 1 hours.