Question

A conveyor belt 1.3 m off the floor carry widgets to an open shipping crate at a rate of 1.8 m/s. Where should the crate be placed on the floor so the widgets land in the center of the crate?

Answer 1

The direction of motion ( along horizontal) is the X axis, vertically upward is Y axis.

Acceleration of gravity is vertically downwards,

Initial velocity is horizontal, , Initial vertical velocity

Initial height of widget

Finally the widget is on ground. Hence vertical displacement of object is

X displacement of the object is .

Using

----(1)

-----(2)

from (1) and (2)

The crate must be placed at a distance of from the end of the belt so that widget lands in the center of the crate.