Question

Change the Gravity to 9.80 m/s²_.. Keep the height of the cannon at ground level.

1. Determine what angles you must have the cannon tilted at to have the cannon ball land at the target 20.5 m away when you have an initial speed of 20 m/s using the simulation. Let the mass of the cannon ball remain at 17.60 kg and the diameter at 0.18 m. Then use the Range formula R=v02sin(2θ)g to verify the angles. (Hint: recall from Trigonometry that sine can be positive in Quadratic I and Quadrant II—Use the Reference Angle Theorem). Ask you instructor if you have any trouble verifying the angle with the Range formula.
2. Use the Time, Range, and Height tool to determine the total amount of time the cannon was in the air (slide the tool to the landing point to list the time the cannon took to reach the ground). Use the equations from Chapter 3 to verify the time it takes the cannon to reach the ground.
3. Now change to initial velocity to 15 m/s. Find the angle that will allow for the maximum horizontal displacement when the object is launched at the same level it will land.
4. Now try changing the object to a different object (with a different mass and shape). Compare the trajectory of both motions. You can try several different objects with various mass and size. Are the trajectories different (different horizontal distance, different maximum heights, etc.) for each of the objects? Does mass play a role in the launch given that the objects leave with the same initial velocity?

Answer 1

also, mass of the projectile body is independent of horizontal displacement in the projectile morion. The horizontal displacement , height reached by projectile and time of travelling are depends on initial projecting speed , angle of projection and acceleration due to gravity. Mass have no role in these parameters. .