Consider a tank full of water, cylindrical in shape, 3.0 meters high and 1.0 meter in diameter. Suppose there is a hole of area 1.0 cm2 at the bottom of the tank. Calculate (a) the speed with which water is discharged, then (b) the volume of water discharged each second.
a) Let the speed of the water discharged is v.
The height of the tank is h=3.0 m.
The area of the hole is a=1.0 cm2=0.0001 m2.
From the Bernoulli's theorem, we can say the speed is
The speed of the water discharged is 7.668115805 m/s or 7.67 m/s approximately.
b) Let the volume of water discharged each second is V.
We know the volume of water discharged per second is
The volume of water discharged each second is 7.6710-4 m3 approximately.
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