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If you throw a ball at an angle a and an initial speed of 1m/s, then...

If you throw a ball at an angle a and an initial speed of 1m/s, then its trajectory at time t is given by (x, y) = (t cos(a), tsin(a) − 5t^2). What is the angle you need to throw at to ensure that it hits the ground (y = 0) the furthest possible from where you are standing (at (x, y) = (0, 0))? How far will it go?

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