Question

Fifteen amps of current flow into a junction with four exits.  One exit carries 2.5A, and another two carry 6.2A each.  The remaining current is

         A) 0.015A         B) 0.10A          C) 1.5A           D) 15A

Answer 1

This question can be solved with the help of kirchoff's current law.  

According to kirchoff's current law "the total current entering the junction is equal to the total current leaving the same junction".

It can also be stated that the algebraic sum of all the current entering the junction is equal to the algebraic sum of current leaving the same junction

Total current (I) entering the junction = total current leaving the same junction.

  I=i1+i2+i3+i4

15=2.5+6.2+6.2+i4

15=14.9+i4

i4= 15-14.9

  i4= 0.10 Ampere

Hence, option b is correct i.e. 0.10 Ampere