Question

A particle with a
charge of −1.24×10−8C is moving with instantaneous velocity
*v*⃗ = (4.19×104m/s)*i*^ + (−3.85×104m/s)*j*^
.

Part A

What is the force
exerted on this particle by a magnetic field
*B*⃗ = (1.40 T ) *i*^?

Enter the *x*,
*y*, and *z* components of the force separated by
commas.

**Part
B**

What is the force
exerted on this particle by a magnetic field
*B*⃗ = (1.40 T ) *k*^?

**Please solve
and show how you get the z component from the x and y components in
the solution**

Enter the *x*,
*y*, and *z* components of the force separated by
commas.

Answer #1

A particle with a charge of −1.24E-8 C is moving with
instantaneous velocity v⃗ = (4.19E4 m/s)(i) + (−3.85E4
m/s )(j).
What is the force exerted on this particle by a magnetic field
B= (1.50 T ) (i)? Forces in x, y, and z.
What is the force exerted on this particle by a magnetic field
B= (1.50 T ) (k)? Forces in x, y, and z.
Please show ALL work.

A negative charge q = −3.00×10−6 C is located at the origin and
has velocity υ⃗ =(7.50×104m/s)i+((−4.90)×104m/s)j.
A) At this instant what is the magnetic field produced by this
charge at the point x = 0.200 m , y = -0.310 m ,
z = 0?
Enter the x, y, and z components of
the magnetic field separated by commas.

A particle with charge − 5.10 nC is moving in a uniform magnetic
field B⃗ =−( 1.25 T )k^. The magnetic force on
the particle is measured to be F⃗ =−( 4.00×10−7
N )i^+( 7.60×10−7 N )j^
.
Part A
Are there components of the velocity that are not determined by
the measurement of the force?
yes
no
Part D
Calculate the scalar product v⃗ ⋅F⃗.
v⃗ ⋅F⃗
m/s⋅N
Request Answer
Part E
What is the angle between v⃗
and...

(HW09-28.7) A negative charge q = ?3.40×10?6
C is located at the origin and has velocity ??
=(7.50×104m/s)?^+((?4.90)×104m/s)j^.
A) At this instant what is the magnetic field produced by this
charge at the point x = 0.250 m , y = -0.250 m ,
z = 0?
Enter the x, y, and z components of
the magnetic field separated by commas.
Bx, By, Bz
=

An electron with a velocity given by v⃗ =(1.6×105 m/s
)x^+(6700 m/s )y^ moves through a region of space with a magnetic
field B⃗ ==(0.26 T )x^−(0.10 T )z^ and an electric field E⃗ =(220
N/C )x^.
Using cross products, find the magnitude of the net force acting
on the electron. (Cross products are discussed in Appendix A.)
Express your answer using two significant figures.

A -5.00 μC charge is moving at a constant speed of
6.90×105 m/s in the +x−direction relative to a
reference frame. At the instant when the point charge is at the
origin, what is the magnetic-field vector it produces at the
following points.
Part A
x=0.500m,y=0, z=0
Enter your answers numerically separated by commas.
Bx,By,Bz
=
nothing
T
SubmitRequest Answer
Part B
x=0, y=0.500m, z=0
Enter your answers numerically separated by commas.
Bx,By,Bz
=
nothing
T
SubmitRequest Answer
Part C...

A particle with a charge of − 5.30 nCnC is moving in a uniform
magnetic field of B⃗ =−(B→=−( 1.25 TT )k^k^. The magnetic force on
the particle is measured to be
F⃗ =−(F→= −( 3.00×10−7 NN )i^+()i^+(
7.60×10−7 NN )j^)j^.
What is the angle between v⃗ v→v_vec and F⃗ F→F_vec?
Express your answer in degrees to three significant
figures.

A mass mAmAm_A = 1.8 kgkg , moving with velocity v⃗
A=(4.0iˆ+4.4jˆ−1.2kˆ)m/sv→A=(4.0i^+4.4j^−1.2k^)m/s, collides with
mass mBmBm_B = 3.8 kgkg , which is initially at rest. Immediately
after the collision, mass mAmAm_A = 1.8 kgkg is observed traveling
at velocity v⃗ ′A=(−2.4iˆ+3.0kˆ)m/sv→′A=(−2.4i^+3.0k^)m/s.
Find the velocity of mass mBmB after the collision. Assume no
outside force acts on the two masses during the collision.
Enter the x, y, and z components of the velocity separated by
commas. Express your answer to two...

A particle with charge − 5.70 nC is moving in a uniform magnetic
field B⃗ =−(B→=−( 1.23 T )k^. The magnetic force on the particle is
measured to be F⃗ =−(F→=−( 3.00×10−7 N )i^+(
7.60×10−7 N )j^.
A) Calculate the x-component of the velocity of the
particle.
B) Calculate the y-component of the velocity of the
particle.
C) Calculate the scalar product v⋅F
D) What is the angle between v and F ? Give
your answer in degrees.

A particle with charge ? 5.50 nC is moving in a uniform magnetic
field B? =?( 1.24 T )k^. The magnetic force on
the particle is measured to be F? =?( 3.40×10?7
N )i^+( 7.60×10?7 N )j^.
(A) Are there components of the velocity that are not determined
by the measurement of the force?
(D)Calculate the scalar product v? ?F? ?
(E) What is the angle between v? and
F? ? Give your answer in degrees?

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