Question

A 0.40000000000000002 kg ball is thrown up with an initial velocity of 26 m/s, how much its velocity at the height of 7 m.

Answer 1

Using Equation of motion Under gravity,

Where,

v - Final velocity

u - Initial Velocity

g - Acceleration due to gravity

h - height

given values,

v = to be determined

u = 26 m/s

g= -9.8 m/s^2

h = 7 m

Solving for v, and putting values in equation.

  

Considering positive value,

The velocity after reaching at height 7 m is,

v= 23.21 m/s. /*Answer*/