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A 5 liter tank holds a sample of gas under an absolute pressure of 590 kPa...

A 5 liter tank holds a sample of gas under an absolute pressure of 590 kPa and a temperature of 51 degrees C. What will be the new pressure if the same sample of gas is placed into a 3 liter container at 10 degrees C.

New Pressure = kPa

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Answer #1

Pressure of the gas in the first tank = P1 = 590 kPa = 590 x 103 Pa

Volume of the first tank = V1 = 5 L = 5 x 10-3 m3

Temperature of the gas in the first tank = T1 = 51 oC = 51 + 273 K = 324 K

Pressure of the gas in the second tank = P2

Volume of the second tank = V2 = 3 L = 3 x 10-3 m3

Temperature of the gas in the second tank = T2 = 10 oC = 10 + 273 K = 283 K

P2 = 858.9 x 103 Pa

P2 = 858.9 kPa

New pressure of the gas in the 3 liter container = 858.9 kPa

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