Question

A 1,900 kg vehicle traveling east on Anderson Avenue at 59.0
km/hr collides with a 3,800 kg vehicle traveling north across
Anderson Avenue at 21.0 km/hr. If they stick together on collision,
what is the magnitude and direction of their velocity just after
colliding?

__________ km/hr

__________ ° north of east.

Answer #1

Given that

The mass of the first vehcile (m1) =1900kg

Mass of the second vehcile(m2) =3800kg

Initial velocity of the first vehicle is(vi) =59km/hr =16.3889m/s

Initial Velocity of the second vechile (v2) =21km/hr = 5.833m/s

The final velocity of the vechicle after collision is given from the conservation of momentum

m1v1+m2v2 =(m1+m2)v

v =m1v1+m2v2/(m1+m2)

=1900*16.3889i+3800*5.833j/(1900+3800) =

=5.4629i+3.8886j m/s

=19.666i+13.998j km/hr

The magnitude and direction of their velocity just after colliding is given

theta =tan-1(3.8886/5.4629) =35.444degrees of north of east

The magnitude of direction is given by

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B) What is the speed of the wreckage just after the
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please show all work so I can actually learn this.
thanks.

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