Question

A tiny drop of dye is put in a very still tub of water. The dye molecules travel about 10^-11 m between collisions and undergo about 4

Answer 1

Total distance travelled by the die molecules in 410¹³ collision is = 10(410¹³)m   if s=10m

Total distanace covered by the die molecules in 410¹³ collision is = 11( 410¹³) m if s=11m

Average distance covered by the die molecule per second= (10+11)/2 ( 410¹³) m

                                                                                                          =10.5(410¹³)m

mean deviation of the distance covered by the die molecules= 0.5(410¹³)m

The average distance covered by the die molecules per hour= 60(10.5)(410¹³)

                                                                                                               =252010¹³ m

The mean deviation is = 600.5410¹³m

Average distaance per year=   3.1710⁷(10.5)(410¹³)= 133.1410²⁰ m

the mean deviation per year= 3.1710⁷(0.5)(410¹³)=6.3410²⁰m