Question

# A.) Consider a non-rotating space station in the shape of a long thin uniform rod of...

A.) Consider a non-rotating space station in the shape of a long thin uniform rod of mass 4.96 x 10^6 kg and length 530 meters. Rocket motors on both ends of the rod are ignited, applying a constant force of F = 4.99 x 10^5 N to each end of the rod as shown in the diagram, causing the station to rotate about its center. If the motors are left running for 1 minutes and 28 seconds before shutting off, then how fast will the station be rotating when the engines stop?

Multiple choice

- 1.34 rpm

- 2.29 rpm

- 3.44 rpm

- 1.91 rpm

B.) This time we have a non-rotating space station in the shape of a long thin uniform rod of mass 4.89 x 10^6 kg and length 1182 meters. Small probes of mass 6526 kg are periodically launched in pairs from two points on the rod-shaped part of the station as shown, launching at a speed of 3389 m/s with respect to the launch points, which are each located 385 m from the center of the rod. After 13 pairs of probes have launched, how fast will the station be spinning?

Multiple choice

- 3.71 rpm

- 1.86 rpm

- 4.82 rpm

- 1.12 rpm

A) 1.91 rpm

moment of inertia of space station, I = M*L^2/12

angular acceleration, alfa = Torque/I

= 2*F*r/I

= 2*F*(L/2)/(M*L^2/12)

= 2*4.99*10^5*(530/2)/(4.96*10^6*530^2/12)

angular velocity after t = 1 minute 28 s = 88 s

w = wo + alfa*t

= 0 + 0.0022778*88
= 0.2004*60/(2*pi) rev/min
= 1.91 rmp

B) 3.71 rpm

given
M = 4.89*10^6 kg
L = 1182 m
m = 6526 kg
v = 3389 m/s
r = 385 m

Apply conservation of momentum

angular momentum of rod = angular momentum of 13 pairs of probes

I*w = 2*13*m*v*r

(M*L^2/12)*w = 26*m*v*r

w = 26*m*v*r/(M*L^2/12)

= 26*6526*3389*385/(4.89*10^6*1182^2/12)

= 0.38886*60/(2*pi) rev/min

= 3.71 rpm

#### Earn Coins

Coins can be redeemed for fabulous gifts.