Question

A frictionless simple pendulum on earth has a period of 1.2 seconds. On planet X its...

A frictionless simple pendulum on earth has a period of 1.2 seconds. On planet X its frequency of oscillation is 1.2 Hz.
What is the acceleration due to gravity on planet X in units of meters per second squared?
16.9
6.8
20.3
14.1
9.8
Science   Advanced-Physics   
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Answer #1

The time period of a simple pendulum of length L is given by

Let T=TE be the time period of the pendulum on Earth, and g=gE be the gravitational acceleration on Earth.

Substituting TE=1.2 s and gE=9.8m/s2 we get

Given the frequency on planet X is fX=1.2Hz. The time period of oscillation is

To find gravitational acceleration on planet X we use

Substituting values

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