Question

The tires of a car make 91 revolutions as the car reduces its speed uniformly from 95.0 km/hkm/h to 62.0 km/hkm/h . The tires have a diameter of 0.90 mm .

a. What was the angular acceleration of the tires?

b. If the car continues to decelerate at this rate, how much more time is required for it to stop?

c.How far does the car go? Find the total distance.

Answer #1

The tires of a car make 77 revolutions as the car reduces its
speed uniformly from 87.0 km/h to 55.0 km/h. The tires have a
diameter of 0.90 m.
A) What was the angular acceleration of the tires?
B) If the car continues to decelerate at this rate, how much
more time is required for it to stop?
C) If the car continues to decelerate at this rate, how far does
it go? Find the total distance.

The tires of a car make 62 revolutions as the car reduces its
speed uniformly from 95.0 km/h to 59.0 km/h . The tires have a
diameter of 0.84 m. A) What was the angular acceleration of the
tires? B) If the car continues to decelerate at this rate, how much
more time is required for it to stop? C) How far does the car go?
Find the total distance.

The tires of a car make 68 revolutions as the car reduces its
speed uniformly from 91.0 km/h to 60.0 km/h. The tires have a
diameter of 0.80 m.
What was the angular acceleration of the tires?
If the car continues to decelerate at this rate, how much more
time is required for it to stop?
If the car continues to decelerate at this rate, how far does it
go? Find the total distance.

The tires of a car make 75 revolutions as the car reduces its
speed uniformly from 92.0 km/h to 61.0 km/h. The tires have a
diameter of 0.82 m.
What was the angular acceleration of the tires?
a= ? rad/s^2
If the car continues to decelerate at this rate, how much more
time is required for it to stop?
If the car continues to decelerate at this rate, how far does it
go? Find the total distance.

The tires of a car make 61 revolutions as the car reduces its
speed uniformly from 93.0 km/h to 63.0 km/h. The tires have a
diameter of 0.80 m.
Part A What was the angular acceleration of the
tires?
Part B If the car continues to decelerate at
this rate, how much more time is required for it to stop?
Part C If the car continues to decelerate at
this rate, how far does it go? Find the total distance.

The tires of a car make 70 revolutions as the car reduces its
speed uniformly from 94.0 km/h to 62.0 km/h. The tires have a
diameter of 0.86 m. If the car continues to decelerate at this
rate, how far does it go? Find the total distance.

The tires of a car make 74 revolutions as the car reduces its
speed uniformly from 86 km/h to 43 km/h . The tires have a diameter
of 0.81 m .What was the angular acceleration of the tires?If the
car continues to decelerate at this rate, how much more time is
required for it to stop?

The tires of a car make 56 revolutions as the car reduces its
speed uniformly from 93 km/h to 50 km/h . The tires have a diameter
of 0.76 m .
A)What was the angular acceleration of the tires?
B)If the car continues to decelerate at this rate, how much more
time is required for it to stop?

The tires of a car make 45 revolutions as the car reduces its
speed uniformly from 120 km/h to 50 km/h. The tires have a diameter
of 0.80 m.
(a) What was the angular acceleration of the tires?
____ rad/s2
(b) If the car continues to decelerate at this rate, how much more
time is required for it to stop?
____s

The tires of a car make 78 revolutions as the car reduces its
speed uniformly from 87.0 km/h to 57.0 km/h. The tires have a
diameter of 0.82 m. Part A What was the angular acceleration of the
tires? Express your answer using two significant figures. Part B If
the car continues to decelerate at this rate, how much more time is
required for it to stop? Express your answer to two significant
figures and include the appropriate units. Part...

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