Two objects collide head on. Assume they have equal masses but unequal velocities, such that the one coming in from the right is moving at 23.92 m/s toward the left, and the one coming in from the left is moving at 86.56 m/s toward the right. After the collision, what is the velocity of the one that came in from the left? (Use + to the right and - to the left to distinguish direction in your answer.) Give your answer in m/s.
here,
the masses of each is m
the initial velocity of 1 , u1 = - 23.92 m/s
the initial velocity of 2 , u2 = 86.56 m/s
let the final velocities after the collison be v1 and v2
using conservation of momentum
m *u1 + m * u2 = m * v1 + m * v2
- 23.92 + 85.56 = v1 + v2 ....(1)
and
using conservation of kientic energy
0.5 * m *u1^2 + 0.5 * m * u2^2 = 0.5 * m * v1^2 + 0.5 * m * v2^2
23.92^2 + 85.56^2 = v1^2 + v2^2 ....(2)
from (1) and (2)
v2 = - 23.92 m/s
v1 = 85.56 m/s
the velocity of the one that came in from the left is 85.56 m/s to the left
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