An ant, crazed by the Sun on a hot Texas afternoon, darts over an xy plane scratched in the dirt. The x and y components of four consecutive darts are the following, all in centimeters: (33.0, 48.0), (bx, -71.0), (-22.0, cy), (-86.0, -60.0).The overall displacement of the four darts has the xy components (-120, -29.0).What are (a) bx and (b) cy? What are the (c) magnitude and (d) angle (counterclockwise from the positive direction of the x axis) of the overall displacement?
Suppose, X-component of the overall displacement = Dx
and Y-component of the overall displacement = Dy
(a) We have -
Dx = ax + bx + cx + dx
=> -120 = 33.0 + bx -22.0 - 86.0
=> -120 = -75.0 + bx
=> bx = -45 cm
(b) Dy = ay + by + cy + dy
=> -29.0 = 48.0 -71.0 + cy - 60.0
=> -29.0 = -83.0 + cy
=> cy = 54.0 cm
(c) Magnitude, D = Sqrt[Dx^2 + Dy^2]
= Sqrt[(-120)^2 + (-29)^2]
= 123.5 cm
(d) Tan = Dy/Dx
= -120 / -29
= 4.14
=> = tan^-1(4.14) = 76.4 deg
Since, for both x and y cordinates are negative. So, this angle lies in the third quadrant.
So, total angle in counterclockwise from positive direction of x-axis = 180 + 76.4 = 256.4 deg. (Answer)
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