Question

The electrical forces of two point charges mounted on a horizontal rod will be used to...

The electrical forces of two point charges mounted on a horizontal rod will be used to balance the weight of a small sphere with charge Q = +150 μC as shown in the figure. The two point charges each have a charge of – 8.50 μC and are positioned 10 cm apart on the rod. What is the greatest mass the sphere can have without falling? (g = 9.80 m/s2 )

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Find the potential at a point 10 cm above the middle of two point charges of...
Find the potential at a point 10 cm above the middle of two point charges of opposite charge, of magnitude Q = 24 μC, 21 cm apart. What is the magnitude of the field at that point?
Two point charges are initially at rest and they are positioned 25.0 cm apart. The first...
Two point charges are initially at rest and they are positioned 25.0 cm apart. The first charge has a charge of 10.0 micro Coulombs and the second charge has a charge of 50.0 micro Coulombs. The second charge has twice the mass as the first charge. When the point charges are 50.0 cm apart what is the kinetic energy of the second charge?
Positive point charges q = 7.00 μC and q′= 2.00 μC are moving relative to an...
Positive point charges q = 7.00 μC and q′= 2.00 μC are moving relative to an observer at point P, as shown in the figure (Figure 1). The distance d is 0.130 m , v = 4.60×106 m/s , and v′= 9.20×106 m/s . When the two charges are at the locations shown in the figure, what is the magnitude of the net magnetic field they produce at point P? What is the direction of the net magnetic field at...
Positive point charges q = 8.00 μC and q′= 4.00 μC are moving relative to an...
Positive point charges q = 8.00 μC and q′= 4.00 μC are moving relative to an observer at point P, as shown in the figure (Figure 1). The distance d is 0.120 m , v = 4.60×106 m/s , and v′= 9.20×106 m/s . When the two charges are at the locations shown in the figure, what is the magnitude of the net magnetic field they produce at point PP? Express your answer in teslas. What is the magnitude of...
Two small beads having positive charges q1 = 28q and q2 = q are fixed at...
Two small beads having positive charges q1 = 28q and q2 = q are fixed at the opposite ends of a horizontal insulating rod of length d = 1.50 m. The bead with charge q1 is at the origin. As shown in the figure below, a third small, charged bead is free to slide on the rod.
Two point charges of charge Q = 17 nC and mass m = 22 g are...
Two point charges of charge Q = 17 nC and mass m = 22 g are 39 cm apart. One of them is let go. Gravity should be ignored. What will its speed be when it has moved 17 cm?
Two point charges 1.8 cm apart have an electric potential energy -200 μJ . The total...
Two point charges 1.8 cm apart have an electric potential energy -200 μJ . The total charge is 35 nC . What are the two charges?
Two negative and two positive point charges (magnitude Q = 3.51 mC ) are placed on...
Two negative and two positive point charges (magnitude Q = 3.51 mC ) are placed on opposite corners of a square as shown in the figure (a = 0.170 m ) a.) Determine the magnitude of the force on each charge. F1,F2,F3,F4 b.)Determine the direction of the force on each charge.
a) The figure shows an arrangement of two -1.9 nC charges, each separated by 5.0 mm...
a) The figure shows an arrangement of two -1.9 nC charges, each separated by 5.0 mm from a proton. If the two negative charges are held fixed at their locations and the proton is given an initial velocity v as shown in the figure, what is the minimum initial speed v ( in km/s) that the proton needs to totally escape from the negative charges? (k = 1/4πε0 = 8.99 × 109 N.m2/C2, e = 1.60 × 10-19 C, mproton...
Two point charges of −Q and Q are fixed at x=−a and x=a on the x...
Two point charges of −Q and Q are fixed at x=−a and x=a on the x axis, respectively as shown in Figure 1. Another point charge of q and mass m is released at x=x0 at rest and it is free to move. Find a) the electric field vector, −→E (both magnitude and direction) at any x and b) the ultimate speed of particle of mass m.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT