Question

A converging lens (f1 = 24.0 cm) is located 56.0 cm to the left of a diverging lens (f2 = -28.0 cm). An object is placed to the left of the converging lens, and the final image produced by the two-lens combination lies 21.1 cm to the left of the diverging lens. How far is the object from the converging lens?

Answer #1

A converging lens (f1 = 24.0 cm) is located
56.0 cm to the left of a diverging lens (f2 =
−28.0 cm). An object is placed to the left of the converging lens,
and the final image produced by the two-lens combination lies 22.1
cm to the left of the diverging lens. How far is the object from
the converging lens?

A converging lens (f1 = 24.0 cm) is located 56.0 cm to the left
of a diverging lens (f2 = -28.0 cm). An object is placed to the
left of the converging lens, and the final image produced by the
two-lens combination lies 19.4 cm to the left of the diverging
lens. How far is the object from the converging lens?

A converging lens (f1 = 24.0 cm) is located 56.0 cm to the left
of a diverging lens (f2 = -28.0 cm). An object is placed to the
left of the converging lens, and the final image produced by the
two-lens combination lies 20.0 cm to the left of the diverging
lens. How far is the object from the converging lens?

A converging lens (f1 = 24.0 cm) is located
56.0 cm to the left of a diverging lens (f2 =
-28.0 cm). An object is placed to the left of the converging lens,
and the final image produced by the two-lens combination lies 20.7
cm to the left of the diverging lens. How far is the object from
the converging lens (including units)?

A converging lens (f = 11.3 cm) is located 24.0 cm to
the left of a diverging lens (f = -5.42 cm). A postage
stamp is placed 46.0 cm to the left of the converging lens.
(a) Locate the final image of the stamp relative
to the diverging lens. (b) Find the overall
magnification.

A diverging lens (f1 = −13.0 cm) is located 25.0 cm
to the left of a converging lens (f2 = 22.5 cm). A
3.5-cm-tall object stands to the left of the diverging lens,
exactly at its focal point. What is the height of the final image
(including proper algebraic sign)?

8.A diverging lens (f1 = −10.5 cm) is located 43.0 cm to the
left of a converging lens (f2 = 23.5 cm). A 3.0-cm-tall object
stands to the left of the diverging lens, exactly at its focal
point. Determine the distance of the final image relative to the
converging lens (including proper algebraic sign

9. A diverging lens (f1 = −11.0 cm) is located 21.0 cm to the
left of a converging lens (f2 = 23.5 cm). A 3.0-cm-tall object
stands to the left of the diverging lens, exactly at its focal
point. What is the height of the final image (including proper
algebraic sign)? cm

A 2.05-cm-tall object is placed 30.0 cm to the left of
a converging lens with a focal length f1 = 21.0 cm . A diverging
lens, with a focal length f2 = -42.5 cm , is placed 30.0 cm to the
right of the first lens.
How tall is the final image of the object?________cm

A 2.05-cm-tall object is placed 30.0 cm to the left of a
converging lens with a focal length f1 = 20.5 cm . A diverging
lens, with a focal length f2 = -42.5 cm , is placed 30.0 cm to the
right of the first lens.
Q:How tall is the final image of the object?

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