Question

Calculate the amount of heat energy required to

change *0.173* kg of ice at a temperature of *-35* �C
to steam at a

temperature of *160* �C. (specific heat capacities

of ice, water and steam are *2090, 4180, 2010* J ⁄ kg ⁄
�C

respectively. Latent heat of fusion and vaporization of water
are

*3.34e5, 2.26e6* J ⁄ kg respectively.)

Answer #1

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How much energy is required to change a 23 g ice cube from ice
at − 12 ◦ C to steam at 101 ◦ C? The specific heat of ice is 2090 J
/ kg · ◦ C and of water 4186 J / kg · ◦ C. The latent heat of
fusion of water is 3 . 33 × 10^5 J / kg, its latent heat of
vaporization is 2 . 26 × 10^6 J / kg, and the...

How much energy is required to change a 34 g ice cube from ice
at −10◦C to steam at 119◦C? The specific heat of ice is 2090 J/kg ·
◦ C, the specific heat of water is 4186 J/kg · ◦ C, the specific
heat of stream is 2010 J/kg · ◦ C, the heat of fusion is 3.33 × 105
J/kg, and the heat of vaporization is 2.26 × 106 J/kg. Answer in
units of J

17. How much heat is required to change the temperature of 50 g
of ice cube initially at - 30 0C to steam at 160
0C? (Express your answer in J){ specific heat of ice is
2090 J/kg 0C, that of water is 4186 J/kg 0C,
that of steam is 2010 J/kg 0C; Lf = 3.33 X 10 J/kg, Lv =
2.26 X 10 J/kg.}

Calculate the amount of heat required to change 35.0g ice at
-25.0 C to steam at 125 C (Heat of fusion = 333 J/g; heat of
vaporization = 2260 J/g; Specific heats: ice = 2.09 J/g*K, water =
4.18 J/g*K, steam = 1.84 J/g*K)

Calculate the amount of heat required to change 35.0 g ice at
-25.0ºC to steam at 125ºC. (Heat of fusion = 333 J/g; heat of
vaporization = 2260 J/g; specific heats: ice = 2.09 J/g·K, water =
4.18 J/g·K, steam = 1.84 J/g·K)

A 60 kg block of ice begins at -60 degrees the specific heat of
ice is 2090 j/(kg)C. The latent heat of fusion of water is 3.3 x
10^5 and the latent heat of vaporization is 2.3 x 10^6 J/kg. How
much energy is required to heat the ice to 0 degrees Celcius
(melting point)?
How much energy is required to heat the ice from -50C to the
melting point and melt the ice?
How much energy is required to...

To change 25 kg of ice -10°C to steam 100°C, how much heat is
required? The specific heat of water is 4.184 kJ/kg. K. The latent
heat of fusion for water at 0°C is approximately 334 kJ/kg (or 80
cal/g), and the latent heat of vaporization at 100°C is about 2,230
kJ/kg (533 cal/g).

How much energy is required to change a 35 g
ice cube from ice at ?7
?C to steam at 108?C?
The specific heat of ice is 2090 J/kg

You initially have 2.0kg of ice in 3.0kg of water at 0°C. How
much total heat must be added in order to convert 2.0kg of the
entire sample to steam at 100°C? Separately determine the amount of
heat for each stage of this process.
Specific heat capacities (J/kg∙K) Latent heats (J/kg)
c ice = 2090 Lf = 33.5∙10^4
c water = 4186 Lv = 22.6∙10^5
c steam = 2010

How much thermal energy (in J) is required to boil 2.25 kg of
water at 100.0°C into steam at 149.0°C? The latent heat of
vaporization of water is 2.26 ✕ 106 J/kg and the
specific heat of steam is
2010
J
kg · °C
.

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