Calculate the induced electric field (in V/m) in a 60-turn coil with a diameter of 11 cm that is placed in a spatially uniform magnetic field of magnitude 0.60 T so that the face of the coil and the magnetic field are perpendicular. This magnetic field is reduced to zero in 0.10 seconds. Assume that the magnetic field is cylindrically symmetric with respect to the central axi s of the coil. (Enter the magnitude.)
V/m
Given solenoid,
No of turns, N = 60
diameter, d = 11 cm = 0.11 m
initial magnetic field, B1 = 0.60 T
angle beween area vector and magnetic field, = 0 degree | because area vector is perpendicular to plane
final magnetic field, B2 = 0 T
time interval, t = 0.1 s
Induced emf, = -N()
= -NBA/t
= -N( B2 - B1)(d2)/4t
= -60(0 -0.6)(3.14 x 0.112)/4 x 0.1
= 3.42 V/m
Answer: 3.42 V/m
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