Question

a 23 kg object has an initial velocity of 1.4 m/s, but that the end of 0.825 s, its velocity brcomes -1.8 m/s. what is the measure of the average force applied?

Answer 1

The mass of the object is m= 23 kg

Now the initial velocity V1 = 1.4 m/s

Now at the end of t= 0.825 sec

Now the final velocity become V2= -1.8 m/s

Now the average force exert on the object is F

F= m*a

a = acceleration of the object

a = dV/dt = rate of change velocity with respect to time is called acceleration.

F = 89.2 N

This is the average force