Question

Blocks of mass 4, 8, and 20 kg are lined up from left to right in...

Blocks of mass 4, 8, and 20 kg are lined up from left to right in that order on a frictionless surface so each block is touching the next one. A rightward-pointing force of magnitude 18 N is applied to the left-most block.

Suppose now that the left-right order of the blocks is reversed. Now find the magnitude of the force that the leftmost block exerts on the middle one?

F'middle, left =???

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Answer #1

From Newton’s third law of motion the force of middle block on left block will be equal in magnitude of force of left block on the middle block. We use this to find the required solution as shown below

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