A 190-kg object and a 490-kg object are separated by 4.40 m.
Force = G * M1 * M2 /r^2
When the 63 kg particle feels the same force of attration to the 190 and 490 kg objects, the 63 kg object is in equlibrium, so net force = 0 N
G * 490 * 63 /r1^2 = G * 190 * 63/r2^2
490/r1^2 = 190/r2^2
490 * r2^2 = 190 * r1^2
r2^2/ r1^2 = 190/490 = 13/28
r2/r1 = (19/49)^0.5
r2 = r1 * (19/49)^0.5
The is ratio of distances.
The distance to the 490 object is (19/49)^0.5 * the distance to the 190 kg object
If the 190-kg object and a 490-kg object are separated by 4.40 m, r1 + r2 = 4.40
Now you have 2 equations in 2 variables, solve for r1and r2
r1 + r2 = 4.40
r2 = r1 * (19/49)^0.55
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