Question

A ray of light strikes a flat block of glass (n = 1.75) of thickness 1.00 cm at an angle of 45.0° with the normal. Trace the light beam through the glass and find the angles of incidence and refraction at each surface.

Answer 1

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Refractive index of glass, n1 = 1.75
Angle of incidence at 1st surface, = 45.0

Using Snell's Law,
n1 * sin(i) = n2 * sin(r)
1 * sin(45) = 1.75 * sin(r)
r = 23.83^o
Angle of refraction at first surface , r = 23.83^o
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Now by Symmetry ,Angle of incidence at the 2nd Surface = 23.83^o
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Using Snell's Law,
n1 * sin(i) = n2 * sin(r)
1.75 * sin(23.83) = 1 * sin(r)
r = 44.99 ^o
Angle of refraction at 2nd surface , r = 44.99^o

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