A 500g piece of wood (specific gravity =.5) floats in water (density=1.0 g/cm^3).
A. What fraction of its volume will be submerged?
B. A 500g iron weight (density = 7.9g/cm^3) is hung from the bottom of the floating piece of wood. What fraction of the wood is submerged now?
here,
mass of wood , m1 = 500 g
volume of wooden block , v1 = m1 /p1 = 1000 cm^3
a)
equating the forces
buoyant force = weight
volume submerged * pw * g = m1 * g
volume submerged * pw * g = volume * p * g
volume submerged = volume * 0.5
volume submerged /total volume = 0.5
b)
mass of iron , m2 = 500 g
density of iron , p2 = 7.9 g/cm^3
equating the forces
buoyant force = weight
pw * g * ( volume submerged of wood block + volume of iron block) = (m1 + m2) * g
1 * ( volume submerged of wood block + m2/p2) = (500 + 500)
1 * ( volume submerged of wood block + 500/7.9) = (1000)
volume submerged of wooden block = 936.7 cm^3
the fraction of wood submerged now , f = submerged volume of wooden block /total volume
f = 0.94
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