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Two equally charged particles are held 4.1 ✕ 10−3 m apart and then released from rest. The initial acceleration of the...

Two equally charged particles are held 4.1 ✕ 10−3 m apart and then released from rest. The initial acceleration of the first particle is observed to be 5.5 m/s2 and that of the second to be 9.4 m/s2. The mass of the first particle is 6.3 ✕ 10−7 kg.

(a) What is the mass of the second particle? 
 kg 

(b) What is the magnitude of the charge of each particle? 
 C


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Homework Answers

Answer #1

(a) Given,

The  mass of the first particle, m1 = 6.3 * 10−7 kg.

The acceleration of first particle, a1 = 5.5 m/s2

The acceleration of second particle, a2 = 9.4 m/s2

By using Newton's Law

m1a1 = m2a2

6.3 * 10-7 * 5.5 = m2 * 9.4

m2 = 3.68 * 10-7 kg

(b)

We know, F = k q2 / r2

As, F = m1 a1

   = 6.3 * 10-7 * 5.5 = 34.65 * 10-7

So, F = k q2 / r2

34.65 * 10-7 = 9 * 109 * q2 / (4.1* 10-3)2

582.46 * 10-6 * 10-7 = 9 * 109 * q2

q2 = 64.72 * 10-22

q = 8.04 * 10-11 C

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