Question

Two equally charged particles are
held 4.1 ✕ 10^{−3} m apart and
then released from rest. The initial acceleration of the first
particle is observed to be 5.5 m/s^{2} and
that of the second to be 9.4 m/s^{2}. The
mass of the first particle
is 6.3 ✕ 10^{−7} kg.

(a) What is the mass of the second
particle?

kg

(b) What is the magnitude of the charge of each
particle?

C

Answer #1

*(a) Given,*

*The mass of the first particle, m _{1} =
6.3 * 10^{−7} kg.*

*The acceleration of first particle, a _{1} = 5.5
m/s^{2}*

*The acceleration of second particle, a _{2} = 9.4
m/s^{2}*

*By using Newton's Law*

*m _{1}a_{1} =
m_{2}a_{2}*

*6.3 * 10 ^{-7} * 5.5 = m_{2} * 9.4*

*m _{2} = 3.68 * 10^{-7} kg*

*(b)*

*We know, F = k q ^{2} / r^{2}*

*As, F = m _{1} a_{1}*

_{ } = 6.3 * 10^{-7} * 5.5 =
34.65 * 10^{-7}

*So, F = k q ^{2} / r^{2}*

*34.65 * 10 ^{-7} = 9 * 10^{9} * q^{2}
/ (4.1* 10^{-3})^{2}*

*582.46 * 10 ^{-6} * 10^{-7} = 9 *
10^{9} * q^{2}*

*q ^{2} = 64.72 * 10^{-22}*

*q = 8.04 * 10 ^{-11} C*

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