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A 3.65 kg particle with velocity v→=(8.97m/s)î-(4.43m/s)ĵ is at x = 7.38 m, y = 5.02...

A 3.65 kg particle with velocity v→=(8.97m/s)î-(4.43m/s)ĵ is at x = 7.38 m, y = 5.02 m. It is pulled by a 2.09 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing?

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