Question

A projectile is fired at ?_{0}=407.0 m/s at an angle of
?=63.3∘, with respect to the horizontal. Assume that air friction
will shorten the range by 28.1%. How far will the projectile travel
in the horizontal direction, ??

Answer #1

Solution :

We have given :

A projectile is fired at ?_{0} = 407.0 m/s

at an angle of ? = 63.3^{∘} {with respect to the
horizontal}.

And, The air friction will shorten the range by 28.1%.

.

Since the horizontal range of the projectile is given by :

Therefore, Actual horizontal range of the projectile will be :

.

And the horizontal range of the projectile in presence of the air resistance will be :

**R** = R_{0} - (28.1%) R_{0} =
R_{0} - (0.281) R_{0} = (0.719) R_{0} =
(0.719)(13556.158 m) = **9746.88 m**

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