Question

A projectile is fired at ?₀=407.0 m/s at an angle of ?=63.3∘, with respect to the horizontal. Assume that air friction will shorten the range by 28.1%. How far will the projectile travel in the horizontal direction, ??

Answer 1

Solution :

We have given :

A projectile is fired at ?₀ = 407.0 m/s

at an angle of ? = 63.3^∘ {with respect to the horizontal}.

And, The air friction will shorten the range by 28.1%.

.

Since the horizontal range of the projectile is given by :

Therefore, Actual horizontal range of the projectile will be :

.

And the horizontal range of the projectile in presence of the air resistance will be :

R = R₀ - (28.1%) R₀ = R₀ - (0.281) R₀ = (0.719) R₀ = (0.719)(13556.158 m) = 9746.88 m