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An infinite horizontal conducting wire of linear load density lamda=3n C/m is 20 (cm) below a...

An infinite horizontal conducting wire of linear load density lamda=3n C/m is 20 (cm) below a point charge with electric charge q=-5n C . How large is the electric field in a position 40 (cm) below the point load?
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Answer #1

= linear charge density = 3 x 10-9 C/m

r = distance from the point load = 40 cm = 0.40 m

Ewire = electric field by the wire = 2k/r = 2 (9 x 109) (3 x 10-9 )/(0.40) = 135 N/C in down direction

R = distance from the point charge = 60 cm = 0.60 m

Echarge = electric field by charge = kq/R = (9 x 109) (5 x 10-9)/(0.60) = 75 N/C in upward direction

Net electric field is given as

Enet = Ewire - Echarge = 135 - 75 = 60 N/C

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