Question

A proton moves on a circular path in a uniform magnetic field that is perpendicular to...

A proton moves on a circular path in a uniform magnetic field that is perpendicular to the plane of the circle.

Calculate the radius of the circle, if the proton's kinetic energy is K = 0.23 MeV and magnetic field strength is 1.0T.

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.265 T....
An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.265 T. If the kinetic energy of the electron is 4.50 ✕ 10−19 J, find the speed of the electron and the radius of the circular path. (a) the speed of the electron m/s (b) the radius of the circular path μm
A proton moves at 8.00 ✕ 107 m/s perpendicular to a magnetic field. The field causes...
A proton moves at 8.00 ✕ 107 m/s perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radius 0.750 m. What is the field strength (in T)?
A proton moves in uniform circular motion perpendicular to a uniform magnetic field with B =...
A proton moves in uniform circular motion perpendicular to a uniform magnetic field with B = 0.17 T. What is the period of its motion (in s)?
In a nuclear experiment a proton with kinetic energy 4.0 MeV moves in a circular path...
In a nuclear experiment a proton with kinetic energy 4.0 MeV moves in a circular path in a uniform magnetic field. If the magnetic field is B = 1.6 T what is the radius of the orbit? What energy must an alpha particle (q = +2e, m = 4.0 u) and a deuteron (q = +e, m = 2.0 u) have if they are to circulate in the same orbit? Energy of the alpha? (MeV) Energy of the deuteron?
An electron with kinetic energy of 5 x 10^−23 J moves in a circular path of...
An electron with kinetic energy of 5 x 10^−23 J moves in a circular path of radius =2.0 cm inside a solenoid. The magnetic field of the solenoid is perpendicular to the plane of the electron's path. The mass of the electron= 9.1 x 10^−31 kg. a) Find the strength of the magnetic field inside the solenoid. b) Find the current in the solenoid if the solenoid has 25 turns per centimeter.
(A) At what speed (in m/s) will a proton move in a circular path of the...
(A) At what speed (in m/s) will a proton move in a circular path of the same radius as an electron that travels at 7.10 ✕ 106 m/s perpendicular to the Earth's magnetic field at an altitude where the field strength is 1.10 ✕ 10−5 T? (B) What would the radius (in m) of the path be if the proton had the same speed as the electron? (C) What would the radius (in m) be if the proton had the...
(a) At what speed (in m/s) will a proton move in a circular path of the...
(a) At what speed (in m/s) will a proton move in a circular path of the same radius as an electron that travels at 7.00 ✕ 10^6 m/s perpendicular to the Earth's magnetic field at an altitude where the field strength is 1.05 ✕ 10^−5 T? (b) What would the radius (in m) of the path be if the proton had the same speed as the electron? (c) What would the radius (in m) be if the proton had the...
An electron of kinetic energy 40 keV moves in a circular orbit perpendicular to a magnetic...
An electron of kinetic energy 40 keV moves in a circular orbit perpendicular to a magnetic field of 0.375 T. Find the radius of the orbit. find the frequency if the motion.
True or False? ( ) A charge with a velocity perpendicular to a uniform B field...
True or False? ( ) A charge with a velocity perpendicular to a uniform B field will move in a circular path in a plane perpendicular to the B field. ( ) A charge with a velocity perpendicular to a uniform B field will experience a magnetic force of F=qvB ( ) For a mass m to maintain a circular motion on an orbit of radius r, the needed centripetal force is mv/r. ( ) For a mass m to...
A cosmic ray electron moves at 5.25 × 106 m/s perpendicular to the Earth’s magnetic field...
A cosmic ray electron moves at 5.25 × 106 m/s perpendicular to the Earth’s magnetic field at an altitude where the field strength is 1.0 × 10-5 T.What is the radius, in meters, of the circular path the electron follows?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT