A proton moves through a uniform magnetic field given by Vector B = (12.9i -30.7j +19.2k) mT. At time t1, the proton has a velocity given by v = vxi+vyj + (1.88 km/s)k and the magnetic force on the proton is Fb= (5.23e-17N)i +(2.20e-17N)j . (a) At that instant, what is vx? (b) At that instant, what is vy?
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