Question

A transformer has 380 primary turns and 1140 secondary turns. The input voltage is 120 V and the output current is 16.5A . Assume 100% efficiency.

A) What is the output voltage?

B) What is the input current?

Answer #1

N_{p} = number of primary turns = 380

N_{s} = number of secondary turns = 1140

E_{p} = input Voltage = 120 V

I_{s} = 16.5 A

I_{p} = input current

E_{s} = output voltage

since efficiency is 100%

so E_{s} I_{s} = E_{p} I_{p}

E_{s} I_{s} = 120 * I_{p}

E_{s} = 120 * (I_{p}/I_{s})

E_{s} = 120 *
(N_{s}/N_{p})
**( since I _{p}/Is = N_{s}/N_{p}
)**

E_{s} = 120 * (1140/380)

**E _{s} = 360 V**

B)

using **E _{s} I_{s} = E_{p}
I_{P}**

(360) (16.5) = 120* I_{p}

**I _{p} = 49.5 A**

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