A transformer has 380 primary turns and 1140 secondary turns. The input voltage is 120 V and the output current is 16.5A . Assume 100% efficiency.
A) What is the output voltage?
B) What is the input current?
Np = number of primary turns = 380
Ns = number of secondary turns = 1140
Ep = input Voltage = 120 V
Is = 16.5 A
Ip = input current
Es = output voltage
since efficiency is 100%
so Es Is = Ep Ip
Es Is = 120 * Ip
Es = 120 * (Ip/Is)
Es = 120 * (Ns/Np) ( since Ip/Is = Ns/Np )
Es = 120 * (1140/380)
Es = 360 V
B)
using Es Is = Ep IP
(360) (16.5) = 120* Ip
Ip = 49.5 A
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