A 5 kg firecracker is initially traveling to the east at 3 m/s when it splits into two pieces. After the explosion, a 2 kg piece is traveling north at 3 m/s. What is the direction of the velocity of the remaining piece?
a. 45 south of east
b. 31 south of east
c. 68.2 south of east
d. 21.8 south of east
In the absence of any external force, momentum is conserved of the system before and after the explosion.
So by momentum conservation we can find the velocity of the 3kg mass is vector form. From this we can find the direction of the resultant velocity vector wrt east direction.
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