Question

I have a lab, where we have been examining the time it takes for an object...

I have a lab, where we have been examining the time it takes for an object to fall to the ground from a distance of 1.0 m.
After collecting my data, I was asked to graph a distance vs. time squared graph, as seen by the attached photo. The line of best fit is linear.
Now I am being asked to calculate the slope of the best fit line and the acceleration of my object. I am confused as to whether the acceleration is simply the slope of this graph or if I have to do additional calculations. We were given the kinematics equation d = d0 + v0 +(½) a t^2, but I am unsure if it is relevant or how to incorporate it into my acceleration calculation.

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Answer #1

Slope of distance vs. time squared graph gives "acceleration".....

The only case where it may be beneficial to plot distance vs. time squared is if you have motion with constant acceleration and zero initial velocity. In such case the graph of distance vs time squared will be a straight line whose slope is the acceleration.....and in your case also initial velocity is zero and acceleration is constant....

...

Figure was missing

Hope the solution helps..... do comment if any doubts....

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