Question

A blacksmith cools a 1.30 kg chunk of iron, initially at a temperature of 650.0∘C, by...

A blacksmith cools a 1.30 kg chunk of iron, initially at a temperature of 650.0∘C, by trickling 15.4 ∘C water over it. All the water boils away, and the iron ends up at a temperature of 120.0∘C.

How much water did the blacksmith trickle over the iron?

Express your answer with the appropriate units.

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Homework Answers

Answer #1

Solution :

Given :

mass of iron (miron) = 1.3 kg

Initial temperature of iron (Toi) = 650.0o C

Initial temperature of water (Tow) = 15.4o C

Final temperature (Tf) = 120.0o C

According to conservation of energy :

Therefore: Heat lost by iron = Heat gained by water

miron Ciron (Toi - Tf) = mwater { Cwater (100 - Tow) + Cvapour (Tf - 100) + Lvapour }

(1.3) (0.47) (650 - 120) = mwater { (4.186)(100 - 15.4) + (1.996)(120 - 100) + (2260) }

323.83 = mwater { 2654.0556 }

mwater= 0.122 kg

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