Question

A stationary police car emits a sound of frequency 1200 Hz that bounces off of a car on the highway and returns with a frequency of 1230 Hz . The police car is right next to the highway, so the moving car is traveling directly toward or away from it. Part A How fast was the moving car going?

What frequency would the police car have received if it had been traveling toward the other car at 17.0 m/sm/s ?

Express your answer in hertz.

Answer #1

**PART A:**

Let " **V**" be the speed of the car.

**(u + v) / (u-v) =
f _{2} / f_{o}**

**(u + v) / (u-v) = (1230) /
(1200)**

**(343 + v) / (343-v) =
1.025**

**V = 4.23 m/s**
--------------- (**Answer**)

==================================

**PART B:**

**Frequency police car receives will be:**

**f _{2} = f_{o}
[(u + v)/(u-v)] x [(u+v_{p}) / (u - v_{p})
]**

**f _{2} = 1200 x [1.025]
x [ (343 + 17) / (343-17)]**

**f _{2} = 1200 x [1.025]
x [1.10429]**

**f _{2} = 1358
Hz** --------------- (**Answer**)

*(in case of anything wrong/have
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you)*

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