Question

A toroid (having a rectangular cross-section) is constructed from 97.3 turns of wire. The toroid has a height of 1.36 cm. The toroid has an inner radius 0.959 cm and an outer radius 6.42 cm. If the toroid carries a current 2.93 A, evaluate this flux through the turns of the toroid. Answer in units of Wb.

Answer 1

Ans:

Explanation:

Given:

Number of turns , N = 97.3

Hight of the toroid , h = 1.36 cm = 0.0136 m

Inner radius of the toroid ,

Outer radius of the toroid ,

Current through the turns , I = 2.93 A.

we know , the magnetic field for a toroid at an axial distance r is given by,

​​​​​​Also the flus through the turns ,

where dS = hdr = area element for rectangular region.

So total flux ,

Putting all given values ,

So flux through the turns of the toroid is .