Question

DataTable 1
Focal length, f	1.76
2f	3.52
Height of object, ho	4.0

Data Table 2
General Description	Object Dist. (cm)	Image Dist. (cm)	Object Size (cm)	Image Size (cm)	Other Observations (real, virtual or no image?) (Upright or inverted image?)
Object about 5 f	10	74.04	4	-29.62	Real, inverted
Object about 2.5f	10	7.87	4	-3.15	Real, inverted
Object 2f	10	5.44	4	-2.18	Real, inverted
More than f and less than 2f	10	4.29	4	-1.71	Real, inverted
Object at f.	10	2.14	4	-0.86	Real, inverted
Object less than f.	10	1.11	4	-0.44	Real, inverted

Data Table 3
	Trial 1= 2f	Trial 2= f
f (cm)	-3.53	-1.76
do (cm)	10	10
di (cm)	-2.61	-1.5
ho (cm)	4	4
hi (cm)	1.09	0.6
Type of image: real, virtual, none	Virtual	Virtual
Direction of image: inverted or upright	upright	upright

1. For each of the real images you observed, calculate the focal length of the convex lens, using the lens/mirror equation. Do your values agree with each other?
2. Average the values for f found in question 1 and calculate the percent error between this average and the value for f from Data Table 1.
3. Relative to the focal length, how far from the lens should the object be to produce the largest magnification?
4. When does a convex lens act like a magnifying glass?
5. Describe the conditions for forming a virtual image with lenses.
6. How does the image of a concave lens always appear?
7. Where is it located with respect to the lens and the object?

8. The key to understanding a telescope is to remember that the purpose is to gather light from distant objects. The image from the primary lens is magnified by a second lens to increase its size. Why should you use a longer focal length lens as the primary lens and then add other lenses as eyepieces.

to address the comment that the distance should change, i have returned to the simulator. when changing the value of f to 2f 5f, etc. the do did not change.

ive seen the wrror. i will update

Answer 1