Question

The bird (mass .9 kg) flies towards the cat (mass 3.6 kg) with a horizontal velocity of 28 m/s to catch him so the speed of 5 m/s at an angle of 70° above horizontal. At the highest point in the cats jump it catches the bird and holds onto it until hitting the ground. how far from it starting point does the cat hit the ground? Assume ground is flat and they were moving north.

Answer 1

H =maximum height travelled by the cat =

the velocity of cat at maximum height = 5 cos70o = 1.71 m/s

applying conservation of linear momentum at maximum height :

=> = 6.97 m/s

horizontal distance travelled before cathing the bird : R/2 =

After when the cat catches the bird, it's virtical velocity is zero. we can calcucate time to reach the ground :

t =

The distance travelled by them = (1.71 x 0.48) + 0.82 = 1.64 m [answer]