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A +15nC charge is located at (x,y)=(0cm, 15cm ) and a -5.0nC charge is located (x,y)=(...

A +15nC charge is located at (x,y)=(0cm, 15cm ) and a -5.0nC charge is located (x,y)=( 6.0cm ,0cm).


Where would a -15nC charge need to be located in order that the electric field at the origin be zero?
Enter your answers numerically separated by a comma. Express your answer using two significant figures.

x , y = ?
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Homework Answers

Answer #1

Q = 15 x 10^-9

k = 9 x 10^9

r = 0.15 m


E1 will be downwards

vector E1 =magnitude * unit vector = kQ/r^2 * r/|r| = .6 x 10^4 N * [ - 1 j]


E2 will be towards positive x-axis

vector E2 = magnitude * unit vector = 1.25 x 10^4 * [+ 1 i]


resultant = E1+E2 + field due to new charge = 0


En = - E1 - E2

kq/r^2 * r/|r| = 1.25 x 10^4 * [+ 1 i] + 0 .6 x 10^4 N * [ - 1 j]


first equate magnitudes =>


kq/r^2 = 1.3865 x 10^4

r = 9.87 cm = .0987 m


now

kq/r^2 * r/|r| = 1.25 x 10^4 * [+ 1 i] + 0 .6 x 10^4 N * [ - 1 j]


1/r*|r|   = 92.6 i - 44.44 j


1/r = 9.14 i - 4.39 j





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