Question

An alloy has heat of fusion, Lfusion = 63, 000 J/kg. A solid chunk (exactly at the solidification temperature) requires “QL” amount of heat to liquify it. Then an amount “Q” to raise the liquid phase temperature by 48.5◦C. If QL is ten times that of Q, find the specific heat of the alloy in J/(kg· ◦C). Show all work

Answer 1

Solution :

Given :

L_fusion = 63,000 J/kg

dT = 48.5^◦C.

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Let specific heat of alloy be : C_Alloy

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and, QL is ten times that of Q

Q_L = 10 Q

m L_fusion = 10 (m C_Alloy dT)

L_fusion = 10 (C_Alloy dT)

C_Alloy = L_fusion / 10 (dT) = (63,000 J/kg) / (10)(48.5^◦C) = 130 J/(kg·^◦C).

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Therefore :C_Alloy = 130 J/(kg·^◦C).