Question

A door of mass 20 kg, width 1.2 m, height 2.5 m, and thickness 3 cm...

A door of mass 20 kg, width 1.2 m, height 2.5 m, and thickness 3 cm is swinging with an angular velocity of 10 rpm. What is the angular momentum of the door?

a.96 kg*m^2/s

b.10 kg*m^2/s

c. 2.5 kg*m^2/s

d. 63 kg*m^2/s

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Homework Answers

Answer #1

Mass of the door = M = 20 kg

Width of the door = L = 1.2 m

Height of the door = H = 2.5 m

Thickness of the door = T = 3 cm = 0.03 m

When viewed from above the door looks like a rod rotating about it's end.

Moment of inertia of the door = I

I = 9.6 kg.m2

Angular velocity of the door = = 10 rpm = 10 x (2/60) rad/s = 1.047 rad/s

Angular momentum of the door = L

Angular momentum of the door = 10 kg.m2/s

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