Question

Calculate the electrical potential at any point P = (x,y) due to two electrical charges of 5C and 2C located at (0, 0) and (1, 0) respectively and in particular when it is the electrical potential at point (3, 4)? How much is the electric field at any point (x, y) and in particular at (3, 4)?

Note: Write step by step

Answer #1

In contrast to net electric field, when you calculate the
voltage (electrical potential) at a point in space relative to 0 V
(defined as the electric potential halfway between two equal and
opposite charges) – whether it’s due to the presence of one or more
large charges – it is critical for you to include the sign of the
Q’s that are creating the electric field. Why?

Given the electrical potential in a region as V ( x , y ) = (
345^2+ 24510^3+4 ) V , find the x - component of the electric field
( in N / C ) at the point ( 45m , 0 , 0 )

Two point charges q1 and q2 in a x-y coordinator. q1 has a
charge of -3nC and located at (-2m, 0), q2 has a charge of 5nC and
located at (1m, 0). Calculate following:
A) electrical potential at (-1m, 0)
B) electrcal field at (-1m, 0)
C) if a third charge q3 of -2nC is located at (-1m, 0)
position, what is the electrical force on q3.

Point charges of -8mueC, -4 mueC and +8 mueC are
located at the x-axis at x=-1cm X=0 and X=+1 cm respectively.
1)Calculate the electric field at x=3cm
2) Calculate the electric field at x=15cm
3)Locate a point on the positive x axis where the magnitude of the
electric field is zero

Two point charges are fixed in place along the x axis
as shown in the figure above. The charge Q1=-3
μμC is located at the origin. The charge Q2=4
μμC is a distance a = 0.46 m to the right of the
origin.
1)
Calculate the x component of the
electric field at point P a distance
h=0.32 m above the origin.
Ex = -0.115 × 106 N/C
Ex = -0.094 × 106 N/C
Ex = 0.264 × 106 N/C...

Two point charges -7 μC and -2 μC are located at the origin and
a point (0.18 m, 0) respectively. Find the electric field due to
these charges at a point (0.39 m, 0).
a.) E=______ V/m
b.)What is the electric potential at this point?
V=_____V
c.) Find the force acting on a point charge of 5 μC located at this
point.
F=______N

Two positive point
charges are held fixed on the x-axis. Point charge
A is located at the origin, and point charge
B is located at the position x = −5.00 cm =
−5.00✕10-2 m (on the negative x-axis). The
magnitude of charge A is two times greater than
that of charge B: qA =
2qB.
ke = 8.9876✕109
Nm2/C2
(A.) The electric
force on charge A has magnitude 0.344 mN =
0.344⨯10-3 N. What is the electric force (magnitude
and...

GOAL Use the superposition principle to calculate the electric
field due to two point charges. Consider the following
figure.
The resultant electric field at P equals the
vector sum 1 + 2, where 1 is the
field due to the positive charge q1and
2 is the field due to the negative charge
q2.Two point charges lie along the
x-axis in the x y-coordinate plane.
Positive charge q1 is at the origin, and
negative charge q2 is at (0.300 m, 0). Point...

Two
1.58uC point charges are located on the x axis. One is at x =
1.12m, and the other is at x = -1.12m. Determine the electric field
on the y axis at y = 0.518m.
Calculate the electric force on a -3.17uC charge placed on the
y axis at y = 0.518m.

A point charge q1 = -4.00 nC is at the point x = 0.60 m, y =
0.80 m , and a second point charge q2 = +6.00 nC is at the point x
= 0.60 m , y = 0.
Calculate the magnitude of the net electric field at the origin
due to these two point charges.
Calculate the direction of the net electric field at the origin
due to these two point charges. *Counterclockwise from the
+x-direction

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