Question

An object with a height of 8 cm is placed 10 cm in front of a converging lens with a focal lenth of 30 cm.

a) Is the resulting image real or virtual?

b) Draw a ray tracing diagram including all three principle rays.

c) Using the thin-lens equation and the definition of magnification, determine both the image distance and the height of the image. Express your anser in cm, and include any algebraic signs. S’= ____________________________ H’ = ____________________________

Answer 1

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a)

as object distance < focal length, image will be virtual and upright.

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b)

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(c)

thin lens equation

1/f = 1/s + 1/s'

where s is object distance and s' is image distance

so,

1/s' = 1/f - 1/s

1/s' = 1/30 - 1/10

1/s' = -0.066

s' = - 15 cm

negative sign means image is on the same side as the object

and

magnification, m = - s' / s = - (-15 / 10) = 1.5

so,

H' = H * m

H' = 8 * 1.5

H' = 12 cm