Given that:
Wavelength of the light, λ = 532 nm = 532 x 10-9 m
Width of the slit, x = 2.5 x 10-3 mm = 2.5 x 10-6 m
Distance to the screen, L = 20 cm = 0.20 m
Hence, Width of the central maxima (W) is given by:
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