Mass of person, m = 135 lb = 61.235 kg
Height of stairs, h = 2.2 m
Acceleration due to gravity, g = 9.8 m/s2
Hence, Energy consumed for climbing stairs once:
U = mgh
U = (61.235 kg) x (9.8 m/s2) x (2.2 m_
U = 1320.2266 J
We know that 1 kcal = 4184 J
Hence, Calories burned per climb :
U = (1320.2266 J) / (4184 J/kcal)
U = 0.31554 kcal
Hence, No.of climbs to burn excess calories is given by:
N = (excess calories) / (0.31554 kcal)
NOTE : You haven't provided the excess calories consumed. If you have the value, then please comment down below so that I can give you an exact number, or else you can follow the above step.
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