Question

A 22_g wet bar of soap slides down a ramp for a distance x from highest point to the lowest point. The ramp makes an angle of 15.0° with horizontal. Assume frictional constant to be μ_k=0.064. Calculate a) the distance it will cover within 6.8_s, b) acceleration of the soap, and c) its kinetic energy near the end of the ramp, d) what must have been the height of the soap near the starting point.

Answer 1

if x≠s(=44.62m)

Then kinetic energy at the end of ramp

K=(m*a*x)J

And height:H=(xsin15°)m

Where m=mass of soap in kg,a=1.93ms^-2

x in meter